One of these remaining 2 superstars is the most likely winner of this season’s MVP award. Entering the countdown at #2 is the man that will have to carry a team all by himself for the first time in a very long time: The Chef.

#2 Steph Curry

Steph Curry changed the game of basketball to the version that we see and play today. Thanks to Curry, everyone wants to be a 3-point shooter. The absolute limitless range that Curry possesses on the court makes him a near assassin level threat. Arguably the greatest shooter in NBA history, Curry draws the attention of opposition the second he crosses mid-court. However, for the greater half of the past decade, Curry has been flanked by fellow superstars Kevin Durant and Klay Thompson. With those 2 drawing attention, Curry has been able to find space for himself to get open shots. But, this season, Curry with be all by himself on the Warriors. With Durant now a member of the Brooklyn Nets and Thompson out for the season with an injury, Curry will have to prove that he is capable of carrying a team alone. Since 2014, Curry has played 8 games without Durant and Thompson (via FantasyLabs). In those games, Curry has averaged an outstanding 27.5 points per game but all of his other stats suffered. Obviously relied on to do more, Curry’s shooting percentages drop, he has fewer assists and turns the ball over more often. Still, people will see the 27 points a game and submit their MVP vote for him. The real test will be whether Curry can win games without his superstar teammates over the course of an entire season. This past season, Curry was 12th in the NBA in PER with a rate of 24.45 (league average is 15.00). That number will likely see a dip if previous trends hold true. Curry is a former 2x MVP, 1x Scoring Champion, 1x Steals Champion, 6x All-Star, 6x All-NBA player, and 3x NBA Champion.

Curry is currently at +550 (Bovada) to win the NBA MVP award. Do you think Curry will win the MVP? Let me know in the comments below!

-Mitchell Seefeldt

Noah Salzman [CC BY-SA 3.0], via Wikimedia Commons

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